Use Substitution to solve c + t = 30 and 8c + 12t = 268

Publish date: 2024-07-28
Use Substitution to solve c + t = 30 and 8c + 12t = 268 MathCelebrity logo Image to Crop
Use the substitution method to solve:

c + t = 30

8c + 12t = 268

Check Format

Equation 1 is in the correct format.

Check Format

Equation 2 is in the correct format.

Rearrange Equation 2 to solve for c:

8c + 12t = 268

Subtract 12t from both sides to isolate c:

8c + 12t - 12t = 268 - 12t

8c = 268 - 12t

Now divide by 8:
268 - 12t
8

Revised Equation 2:
c  =  268 - 12t
  8

Plug Revised Equation 2 value into c:

1(c) + t = 30

1 * ((268 - 12t)/8) + t = 30

((268 - 12t)/8) + t = 30

Multiply equation 1 through by 8

8 * (((268 - 12t)/8) + t = 30)

8 * (((268 - 12t)/8) + t = 30)

268 - 12t + 8t = 240

Group like terms:

-12t + 8t = 240 - 268

-4t = -28

Divide each side by -4

t  =  -28
  -4

t = 7

Plug this answer into Equation 1

1c + 1(7) = 30

1c + 7 = 30

1c = 30 - 7

1c = 23

Divide each side by 1

c  =  23
  1

c = 23


What is the Answer?

c = 23 and t = 7

How does the Simultaneous Equations Calculator work?

Free Simultaneous Equations Calculator - Solves a system of simultaneous equations with 2 unknowns using the following 3 methods:
1) Substitution Method (Direct Substitution)
2) Elimination Method
3) Cramers Method or Cramers Rule Pick any 3 of the methods to solve the systems of equations 2 equations 2 unknowns
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cramers rulean explicit formula for the solution of a system of linear equations with as many equations as unknownseliminateto remove, to get rid of or put an end toequationa statement declaring two mathematical expressions are equalsimultaneous equations two or more algebraic equations that share variablessubstituteto put in the place of another. To replace one value with anotherunknowna number or value we do not knowvariableAlphabetic character representing a number

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